Base | Representation |
---|---|
bin | 10100100100001011101… |
… | …111000101000011101010 |
3 | 12000002211012111221211002 |
4 | 110210023233011003222 |
5 | 141123304212144432 |
6 | 3001122314035002 |
7 | 204050301261143 |
oct | 24441357050352 |
9 | 5002735457732 |
10 | 1413241131242 |
11 | 4a5396859166 |
12 | 1a9a8b718a62 |
13 | a3363c34585 |
14 | 4c588dc2aca |
15 | 26b65842e62 |
hex | 1490bbc50ea |
1413241131242 has 4 divisors (see below), whose sum is σ = 2119861696866. Its totient is φ = 706620565620.
The previous prime is 1413241131241. The next prime is 1413241131251. The reversal of 1413241131242 is 2421311423141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1375110367801 + 38130763441 = 1172651^2 + 195271^2 .
It is not an unprimeable number, because it can be changed into a prime (1413241131241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 353310282809 + ... + 353310282812.
Almost surely, 21413241131242 is an apocalyptic number.
1413241131242 is a deficient number, since it is larger than the sum of its proper divisors (706620565624).
1413241131242 is an equidigital number, since it uses as much as digits as its factorization.
1413241131242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 706620565623.
The product of its digits is 4608, while the sum is 29.
Adding to 1413241131242 its reverse (2421311423141), we get a palindrome (3834552554383).
The spelling of 1413241131242 in words is "one trillion, four hundred thirteen billion, two hundred forty-one million, one hundred thirty-one thousand, two hundred forty-two".
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