14132441131 has 4 divisors (see below), whose sum is σ = 14134768200. Its totient is φ = 14130114064.

The previous prime is 14132441117. The next prime is 14132441137. The reversal of 14132441131 is 13114423141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14132441131 - 2²¹ = 14130343979 is a prime.

It is a super-2 number, since 2×14132441131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14132441096 and 14132441105.

It is not an unprimeable number, because it can be changed into a prime (14132441137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1154401 + ... + 1166578.

It is an arithmetic number, because the mean of its divisors is an integer number (3533692050).

Almost surely, 2^14132441131 is an apocalyptic number.

14132441131 is a deficient number, since it is larger than the sum of its proper divisors (2327069).

14132441131 is an equidigital number, since it uses as much as digits as its factorization.

14132441131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2327068.

The product of its digits is 1152, while the sum is 25.

Adding to 14132441131 its reverse (13114423141), we get a palindrome (27246864272).

The spelling of 14132441131 in words is "fourteen billion, one hundred thirty-two million, four hundred forty-one thousand, one hundred thirty-one".