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14132500545019 = 16798784128537
BaseRepresentation
bin1100110110100111101010…
…1011001011110111111011
31212001001110021002001021211
43031221322223023313323
53323021330114420034
650020214153343551
72656016352403453
oct315517253136773
955031407061254
1014132500545019
11455961814024a
121702b81a07bb7
137b68c5bb8ccc
1436c033a8ad63
15197943548d64
hexcda7aacbdfb

14132500545019 has 4 divisors (see below), whose sum is σ = 14132584841544. Its totient is φ = 14132416248496.

The previous prime is 14132500545011. The next prime is 14132500545133. The reversal of 14132500545019 is 91054500523141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14132500545019 - 23 = 14132500545011 is a prime.

It is a super-2 number, since 2×141325005450192 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14132500545011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41896282 + ... + 42232255.

It is an arithmetic number, because the mean of its divisors is an integer number (3533146210386).

Almost surely, 214132500545019 is an apocalyptic number.

14132500545019 is a deficient number, since it is larger than the sum of its proper divisors (84296525).

14132500545019 is an equidigital number, since it uses as much as digits as its factorization.

14132500545019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84296524.

The product of its (nonzero) digits is 108000, while the sum is 40.

The spelling of 14132500545019 in words is "fourteen trillion, one hundred thirty-two billion, five hundred million, five hundred forty-five thousand, nineteen".

Divisors: 1 167987 84128537 14132500545019