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14132500545011 is a prime number
BaseRepresentation
bin1100110110100111101010…
…1011001011110111110011
31212001001110021002001021112
43031221322223023313303
53323021330114420021
650020214153343535
72656016352403442
oct315517253136763
955031407061245
1014132500545011
114559618140242
121702b81a07bab
137b68c5bb8cc4
1436c033a8ad59
15197943548d5b
hexcda7aacbdf3

14132500545011 has 2 divisors, whose sum is σ = 14132500545012. Its totient is φ = 14132500545010.

The previous prime is 14132500544999. The next prime is 14132500545133. The reversal of 14132500545011 is 11054500523141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14132500545011 - 26 = 14132500544947 is a prime.

It is not a weakly prime, because it can be changed into another prime (14132500545311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066250272505 + 7066250272506.

It is an arithmetic number, because the mean of its divisors is an integer number (7066250272506).

Almost surely, 214132500545011 is an apocalyptic number.

14132500545011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14132500545011 is an equidigital number, since it uses as much as digits as its factorization.

14132500545011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

The spelling of 14132500545011 in words is "fourteen trillion, one hundred thirty-two billion, five hundred million, five hundred forty-five thousand, eleven".