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14132526483391 = 55858725300493
BaseRepresentation
bin1100110110100111110000…
…1110001000011110111111
31212001001112001212212001021
43031221330032020132333
53323021403234432031
650020220521325011
72656020116024521
oct315517416103677
955031461785037
1014132526483391
114559630847118
121702b8a636767
137b68cb39b364
1436c0372bda11
1519794596e511
hexcda7c3887bf

14132526483391 has 4 divisors (see below), whose sum is σ = 14132552342472. Its totient is φ = 14132500624312.

The previous prime is 14132526483389. The next prime is 14132526483409. The reversal of 14132526483391 is 19338462523141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14132526483391 - 21 = 14132526483389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14132526483791) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12091660 + ... + 13208833.

It is an arithmetic number, because the mean of its divisors is an integer number (3533138085618).

Almost surely, 214132526483391 is an apocalyptic number.

14132526483391 is a deficient number, since it is larger than the sum of its proper divisors (25859081).

14132526483391 is an equidigital number, since it uses as much as digits as its factorization.

14132526483391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25859080.

The product of its digits is 3732480, while the sum is 52.

The spelling of 14132526483391 in words is "fourteen trillion, one hundred thirty-two billion, five hundred twenty-six million, four hundred eighty-three thousand, three hundred ninety-one".

Divisors: 1 558587 25300493 14132526483391