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14132534453 = 69772025589
BaseRepresentation
bin11010010100101110…
…10101110010110101
31100110220212010122222
431022113111302311
5212420412100303
610254205132125
71010134363232
oct151227256265
940426763588
1014132534453
115aa24a1344
1228a4b5a045
131442c0412b
14980d36789
1557aab2938
hex34a5d5cb5

14132534453 has 4 divisors (see below), whose sum is σ = 14134567020. Its totient is φ = 14130501888.

The previous prime is 14132534443. The next prime is 14132534491. The reversal of 14132534453 is 35443523141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3317990404 + 10814544049 = 57602^2 + 103993^2 .

It is a cyclic number.

It is not a de Polignac number, because 14132534453 - 26 = 14132534389 is a prime.

It is a super-3 number, since 3×141325344533 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14132534443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1005818 + ... + 1019771.

It is an arithmetic number, because the mean of its divisors is an integer number (3533641755).

Almost surely, 214132534453 is an apocalyptic number.

It is an amenable number.

14132534453 is a deficient number, since it is larger than the sum of its proper divisors (2032567).

14132534453 is an equidigital number, since it uses as much as digits as its factorization.

14132534453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2032566.

The product of its digits is 86400, while the sum is 35.

The spelling of 14132534453 in words is "fourteen billion, one hundred thirty-two million, five hundred thirty-four thousand, four hundred fifty-three".

Divisors: 1 6977 2025589 14132534453