Base | Representation |
---|---|
bin | 10100100100001100110… |
… | …110111001111111011001 |
3 | 12000002212111221120101220 |
4 | 110210030312321333121 |
5 | 141123324022212111 |
6 | 3001124225402253 |
7 | 204050620312251 |
oct | 24441466717731 |
9 | 5002774846356 |
10 | 1413259960281 |
11 | 4a53a6449754 |
12 | 1a9a95a99389 |
13 | a3367ac7a10 |
14 | 4c58b6c4961 |
15 | 26b67311e06 |
hex | 1490cdb9fd9 |
1413259960281 has 64 divisors (see below), whose sum is σ = 2087731430400. Its totient is φ = 845079941376.
The previous prime is 1413259960261. The next prime is 1413259960303. The reversal of 1413259960281 is 1820699523141.
It is not a de Polignac number, because 1413259960281 - 27 = 1413259960153 is a prime.
It is a super-2 number, since 2×14132599602812 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1413259960261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 64642530 + ... + 64664388.
It is an arithmetic number, because the mean of its divisors is an integer number (32620803600).
Almost surely, 21413259960281 is an apocalyptic number.
It is an amenable number.
1413259960281 is a deficient number, since it is larger than the sum of its proper divisors (674471470119).
1413259960281 is a wasteful number, since it uses less digits than its factorization.
1413259960281 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22278.
The product of its (nonzero) digits is 933120, while the sum is 51.
The spelling of 1413259960281 in words is "one trillion, four hundred thirteen billion, two hundred fifty-nine million, nine hundred sixty thousand, two hundred eighty-one".
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