Base | Representation |
---|---|
bin | 100000001000101010000110… |
… | …001001010001100000011011 |
3 | 200112102020202001111022020002 |
4 | 200020222012021101200123 |
5 | 122011042321232420443 |
6 | 1220331121215123215 |
7 | 41524634504010545 |
oct | 4010520611214033 |
9 | 615366661438202 |
10 | 141332444420123 |
11 | 4103a831389490 |
12 | 13a2721181350b |
13 | 60b279143c268 |
14 | 26c87537c4695 |
15 | 11515ab9382b8 |
hex | 808a8625181b |
141332444420123 has 8 divisors (see below), whose sum is σ = 154181171150256. Its totient is φ = 128483771472000.
The previous prime is 141332444420071. The next prime is 141332444420149. The reversal of 141332444420123 is 321024444233141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 141332444420123 - 210 = 141332444419099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141332444410123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7849586 + ... + 18554807.
It is an arithmetic number, because the mean of its divisors is an integer number (19272646393782).
Almost surely, 2141332444420123 is an apocalyptic number.
141332444420123 is a deficient number, since it is larger than the sum of its proper divisors (12848726730133).
141332444420123 is a wasteful number, since it uses less digits than its factorization.
141332444420123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26891005.
The product of its (nonzero) digits is 221184, while the sum is 38.
Adding to 141332444420123 its reverse (321024444233141), we get a palindrome (462356888653264).
The spelling of 141332444420123 in words is "one hundred forty-one trillion, three hundred thirty-two billion, four hundred forty-four million, four hundred twenty thousand, one hundred twenty-three".
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