Search a number
-
+
14134130323 = 67210957169
BaseRepresentation
bin11010010100111010…
…11011011010010011
31100111000212012210021
431022131123122103
5212421314132243
610254303244311
71010154061015
oct151235333223
940430765707
1014134130323
115aa3391345
1228a55a9697
131443342631
149812301b5
1557acca6ed
hex34a75b693

14134130323 has 4 divisors (see below), whose sum is σ = 14345087560. Its totient is φ = 13923173088.

The previous prime is 14134130321. The next prime is 14134130333. The reversal of 14134130323 is 32303143141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14134130323 - 21 = 14134130321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14134130321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105478518 + ... + 105478651.

It is an arithmetic number, because the mean of its divisors is an integer number (3586271890).

Almost surely, 214134130323 is an apocalyptic number.

14134130323 is a deficient number, since it is larger than the sum of its proper divisors (210957237).

14134130323 is an equidigital number, since it uses as much as digits as its factorization.

14134130323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210957236.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14134130323 its reverse (32303143141), we get a palindrome (46437273464).

The spelling of 14134130323 in words is "fourteen billion, one hundred thirty-four million, one hundred thirty thousand, three hundred twenty-three".

Divisors: 1 67 210957169 14134130323