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141342142151 = 720191734593
BaseRepresentation
bin1000001110100010100…
…1011110111011000111
3111111211101011202122202
42003220221132323013
54303432042022101
6144533124345115
713132406246120
oct2035051367307
9444741152582
10141342142151
1154a40a55431
122348724519b
1310436963852
146bab99d047
153a2398836b
hex20e8a5eec7

141342142151 has 4 divisors (see below), whose sum is σ = 161533876752. Its totient is φ = 121150407552.

The previous prime is 141342142091. The next prime is 141342142177. The reversal of 141342142151 is 151241243141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141342142151 - 222 = 141337947847 is a prime.

It is a super-2 number, since 2×1413421421512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141342145151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10095867290 + ... + 10095867303.

It is an arithmetic number, because the mean of its divisors is an integer number (40383469188).

Almost surely, 2141342142151 is an apocalyptic number.

141342142151 is a deficient number, since it is larger than the sum of its proper divisors (20191734601).

141342142151 is an equidigital number, since it uses as much as digits as its factorization.

141342142151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20191734600.

The product of its digits is 3840, while the sum is 29.

Adding to 141342142151 its reverse (151241243141), we get a palindrome (292583385292).

The spelling of 141342142151 in words is "one hundred forty-one billion, three hundred forty-two million, one hundred forty-two thousand, one hundred fifty-one".

Divisors: 1 7 20191734593 141342142151