Base | Representation |
---|---|
bin | 11010010100111100… |
… | …01111110101011011 |
3 | 1100111001021010100011 |
4 | 31022132033311123 |
5 | 212421343020201 |
6 | 10254312022351 |
7 | 1010155644031 |
oct | 151236176533 |
9 | 40431233304 |
10 | 14134345051 |
11 | 5aa3518702 |
12 | 28a56919b7 |
13 | 14433b92a8 |
14 | 981288551 |
15 | 57ad1e151 |
hex | 34a78fd5b |
14134345051 has 4 divisors (see below), whose sum is σ = 14134586400. Its totient is φ = 14134103704.
The previous prime is 14134345039. The next prime is 14134345067. The reversal of 14134345051 is 15054343141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15054343141 = 41 ⋅367179101.
It is a cyclic number.
It is not a de Polignac number, because 14134345051 - 213 = 14134336859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14134342051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29310 + ... + 170668.
It is an arithmetic number, because the mean of its divisors is an integer number (3533646600).
Almost surely, 214134345051 is an apocalyptic number.
14134345051 is a deficient number, since it is larger than the sum of its proper divisors (241349).
14134345051 is an equidigital number, since it uses as much as digits as its factorization.
14134345051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 241348.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14134345051 its reverse (15054343141), we get a palindrome (29188688192).
The spelling of 14134345051 in words is "fourteen billion, one hundred thirty-four million, three hundred forty-five thousand, fifty-one".
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