Base | Representation |
---|---|
bin | 11010010100111100… |
… | …01111000110100011 |
3 | 1100111001020222020001 |
4 | 31022132033012203 |
5 | 212421342421201 |
6 | 10254312000431 |
7 | 1010155632214 |
oct | 151236170643 |
9 | 40431228201 |
10 | 14134342051 |
11 | 5aa3516425 |
12 | 28a5690117 |
13 | 14433b7b0b |
14 | 98128740b |
15 | 57ad1d301 |
hex | 34a78f1a3 |
14134342051 has 2 divisors, whose sum is σ = 14134342052. Its totient is φ = 14134342050.
The previous prime is 14134342031. The next prime is 14134342097. The reversal of 14134342051 is 15024343141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14134342051 - 29 = 14134341539 is a prime.
It is not a weakly prime, because it can be changed into another prime (14134342031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067171025 + 7067171026.
It is an arithmetic number, because the mean of its divisors is an integer number (7067171026).
Almost surely, 214134342051 is an apocalyptic number.
14134342051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14134342051 is an equidigital number, since it uses as much as digits as its factorization.
14134342051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14134342051 its reverse (15024343141), we get a palindrome (29158685192).
The spelling of 14134342051 in words is "fourteen billion, one hundred thirty-four million, three hundred forty-two thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •