Base | Representation |
---|---|
bin | 10100100100011011010… |
… | …100001010100101010011 |
3 | 12000010111102100110001021 |
4 | 110210123110022211103 |
5 | 141124323120331233 |
6 | 3001204252220311 |
7 | 204056624051431 |
oct | 24443324124523 |
9 | 5003442313037 |
10 | 1413502511443 |
11 | 4a5510354a60 |
12 | 1a9b4316a697 |
13 | a33a612cb09 |
14 | 4c5b19c1d51 |
15 | 26b7d773e2d |
hex | 1491b50a953 |
1413502511443 has 16 divisors (see below), whose sum is σ = 1549029079296. Its totient is φ = 1279156263840.
The previous prime is 1413502511429. The next prime is 1413502511453. The reversal of 1413502511443 is 3441152053141.
It is a cyclic number.
It is not a de Polignac number, because 1413502511443 - 25 = 1413502511411 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1413502511399 and 1413502511408.
It is not an unprimeable number, because it can be changed into a prime (1413502511453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2829121 + ... + 3291037.
It is an arithmetic number, because the mean of its divisors is an integer number (96814317456).
Almost surely, 21413502511443 is an apocalyptic number.
1413502511443 is a deficient number, since it is larger than the sum of its proper divisors (135526567853).
1413502511443 is a wasteful number, since it uses less digits than its factorization.
1413502511443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 463194.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 1413502511443 its reverse (3441152053141), we get a palindrome (4854654564584).
The spelling of 1413502511443 in words is "one trillion, four hundred thirteen billion, five hundred two million, five hundred eleven thousand, four hundred forty-three".
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