1413540153453 has 4 divisors (see below), whose sum is σ = 1884720204608. Its totient is φ = 942360102300.

The previous prime is 1413540153451. The next prime is 1413540153499. The reversal of 1413540153453 is 3543510453141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1413540153453 - 2¹ = 1413540153451 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413540153451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235590025573 + ... + 235590025578.

It is an arithmetic number, because the mean of its divisors is an integer number (471180051152).

Almost surely, 2^{1413540153453} is an apocalyptic number.

It is an amenable number.

1413540153453 is a deficient number, since it is larger than the sum of its proper divisors (471180051155).

1413540153453 is an equidigital number, since it uses as much as digits as its factorization.

1413540153453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471180051154.

The product of its (nonzero) digits is 216000, while the sum is 39.

The spelling of 1413540153453 in words is "one trillion, four hundred thirteen billion, five hundred forty million, one hundred fifty-three thousand, four hundred fifty-three".