Base | Representation |
---|---|
bin | 100000001001110101001111… |
… | …111111101111011010000011 |
3 | 200112200222000220002021021012 |
4 | 200021311033333233122003 |
5 | 122013403102411030430 |
6 | 1220432144432351135 |
7 | 41533522305640343 |
oct | 4011651777573203 |
9 | 615628026067235 |
10 | 141413140330115 |
11 | 41070a810a0a95 |
12 | 13a3a9926a54ab |
13 | 60ba2817b0924 |
14 | 26cc60ab50d23 |
15 | 115373106c695 |
hex | 809d4ffef683 |
141413140330115 has 8 divisors (see below), whose sum is σ = 169727234359968. Its totient is φ = 113109534954880.
The previous prime is 141413140330087. The next prime is 141413140330117. The reversal of 141413140330115 is 511033041314141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141413140330115 - 210 = 141413140329091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141413140330117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2622133991 + ... + 2622187920.
It is an arithmetic number, because the mean of its divisors is an integer number (21215904294996).
Almost surely, 2141413140330115 is an apocalyptic number.
141413140330115 is a deficient number, since it is larger than the sum of its proper divisors (28314094029853).
141413140330115 is an equidigital number, since it uses as much as digits as its factorization.
141413140330115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5244327309.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 141413140330115 its reverse (511033041314141), we get a palindrome (652446181644256).
The spelling of 141413140330115 in words is "one hundred forty-one trillion, four hundred thirteen billion, one hundred forty million, three hundred thirty thousand, one hundred fifteen".
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