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14142033403 = 37382217119
BaseRepresentation
bin11010010101110111…
…00100110111111011
31100111120201201202221
431022323210313323
5212430330032103
610255144504511
71010311205041
oct151273446773
940446651687
1014142033403
115aa789a013
1228a817b137
131444b7b904
149822ca391
1557b83c1bd
hex34aee4dfb

14142033403 has 4 divisors (see below), whose sum is σ = 14524250560. Its totient is φ = 13759816248.

The previous prime is 14142033359. The next prime is 14142033427. The reversal of 14142033403 is 30433024141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30433024141 = 132341001857.

It is a cyclic number.

It is not a de Polignac number, because 14142033403 - 213 = 14142025211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14542033403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191108523 + ... + 191108596.

It is an arithmetic number, because the mean of its divisors is an integer number (3631062640).

Almost surely, 214142033403 is an apocalyptic number.

14142033403 is a deficient number, since it is larger than the sum of its proper divisors (382217157).

14142033403 is an equidigital number, since it uses as much as digits as its factorization.

14142033403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 382217156.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 14142033403 its reverse (30433024141), we get a palindrome (44575057544).

The spelling of 14142033403 in words is "fourteen billion, one hundred forty-two million, thirty-three thousand, four hundred three".

Divisors: 1 37 382217119 14142033403