Base | Representation |
---|---|
bin | 1000001110110101011… |
… | …0010011111011000011 |
3 | 111112000212120021122000 |
4 | 2003231112103323003 |
5 | 4304112234034220 |
6 | 144545022515043 |
7 | 13134354454356 |
oct | 2035526237303 |
9 | 445025507560 |
10 | 141421002435 |
11 | 54a81518319 |
12 | 234a9735a83 |
13 | 1044a0b523b |
14 | 6bb824a29d |
15 | 3a2a864390 |
hex | 20ed593ec3 |
141421002435 has 64 divisors (see below), whose sum is σ = 258330201600. Its totient is φ = 73351910016.
The previous prime is 141421002421. The next prime is 141421002461. The reversal of 141421002435 is 534200124141.
141421002435 is a `hidden beast` number, since 1 + 4 + 14 + 210 + 0 + 2 + 435 = 666.
It is not a de Polignac number, because 141421002435 - 24 = 141421002419 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 141421002399 and 141421002408.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 13516236 + ... + 13526694.
It is an arithmetic number, because the mean of its divisors is an integer number (4036409400).
Almost surely, 2141421002435 is an apocalyptic number.
141421002435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
141421002435 is a deficient number, since it is larger than the sum of its proper divisors (116909199165).
141421002435 is a wasteful number, since it uses less digits than its factorization.
141421002435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13217 (or 13211 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 27.
Adding to 141421002435 its reverse (534200124141), we get a palindrome (675621126576).
The spelling of 141421002435 in words is "one hundred forty-one billion, four hundred twenty-one million, two thousand, four hundred thirty-five".
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