Base | Representation |
---|---|
bin | 10100100101001000100… |
… | …010100011000010010101 |
3 | 12000012110022001200101011 |
4 | 110211020202203002111 |
5 | 141132401340200331 |
6 | 3001411434532221 |
7 | 204114466221613 |
oct | 24451042430225 |
9 | 5005408050334 |
10 | 1414261256341 |
11 | 4a586a67825a |
12 | 1aa115297071 |
13 | a3497399aab |
14 | 4c64468c6b3 |
15 | 26bc519c3b1 |
hex | 149488a3095 |
1414261256341 has 8 divisors (see below), whose sum is σ = 1465290155520. Its totient is φ = 1363383108528.
The previous prime is 1414261256329. The next prime is 1414261256351. The reversal of 1414261256341 is 1436521624141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1414261256341 - 221 = 1414259159189 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1414261256294 and 1414261256303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1414261256311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37668741 + ... + 37706266.
It is an arithmetic number, because the mean of its divisors is an integer number (183161269440).
Almost surely, 21414261256341 is an apocalyptic number.
It is an amenable number.
1414261256341 is a deficient number, since it is larger than the sum of its proper divisors (51028899179).
1414261256341 is an equidigital number, since it uses as much as digits as its factorization.
1414261256341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75375683.
The product of its digits is 138240, while the sum is 40.
The spelling of 1414261256341 in words is "one trillion, four hundred fourteen billion, two hundred sixty-one million, two hundred fifty-six thousand, three hundred forty-one".
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