1414311101122 has 4 divisors (see below), whose sum is σ = 2121466651686. Its totient is φ = 707155550560.

The previous prime is 1414311101041. The next prime is 1414311101123. The reversal of 1414311101122 is 2211011134141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 808904170881 + 605406930241 = 899391^2 + 778079^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1414311101093 and 1414311101102.

It is not an unprimeable number, because it can be changed into a prime (1414311101123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 353577775279 + ... + 353577775282.

Almost surely, 2^{1414311101122} is an apocalyptic number.

1414311101122 is a deficient number, since it is larger than the sum of its proper divisors (707155550564).

1414311101122 is an equidigital number, since it uses as much as digits as its factorization.

1414311101122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 707155550563.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1414311101122 its reverse (2211011134141), we get a palindrome (3625322235263).

The spelling of 1414311101122 in words is "one trillion, four hundred fourteen billion, three hundred eleven million, one hundred one thousand, one hundred twenty-two".