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1414312022021 = 2663531097267
BaseRepresentation
bin10100100101001011100…
…100001101000000000101
312000012120211120211210112
4110211023210031000011
5141133002334201041
63001420451002405
7204115653555533
oct24451344150005
95005524524715
101414312022021
114a58962a1268
121aa12a299405
13a34a4a62862
144c64b305153
1526bc9878deb
hex1494b90d005

1414312022021 has 4 divisors (see below), whose sum is σ = 1414843121952. Its totient is φ = 1413780922092.

The previous prime is 1414312021999. The next prime is 1414312022029. The reversal of 1414312022021 is 1202202134141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1414312022021 - 234 = 1397132152837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1414312022029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265545971 + ... + 265551296.

It is an arithmetic number, because the mean of its divisors is an integer number (353710780488).

Almost surely, 21414312022021 is an apocalyptic number.

It is an amenable number.

1414312022021 is a deficient number, since it is larger than the sum of its proper divisors (531099931).

1414312022021 is an equidigital number, since it uses as much as digits as its factorization.

1414312022021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 531099930.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1414312022021 its reverse (1202202134141), we get a palindrome (2616514156162).

The spelling of 1414312022021 in words is "one trillion, four hundred fourteen billion, three hundred twelve million, twenty-two thousand, twenty-one".

Divisors: 1 2663 531097267 1414312022021