Base | Representation |
---|---|
bin | 11010010110000001… |
… | …00000010001111001 |
3 | 1100111200011100221011 |
4 | 31023000200101321 |
5 | 212431142402210 |
6 | 10255232313521 |
7 | 1010325165364 |
oct | 151300402171 |
9 | 40450140834 |
10 | 14143325305 |
11 | 5aa85a16aa |
12 | 28a86a28a1 |
13 | 1445211955 |
14 | 9825450db |
15 | 57b9e4d8a |
hex | 34b020479 |
14143325305 has 8 divisors (see below), whose sum is σ = 17333096832. Its totient is φ = 11073922608.
The previous prime is 14143325303. The next prime is 14143325327. The reversal of 14143325305 is 50352334141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14143325305 - 21 = 14143325303 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14143325303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30091947 + ... + 30092416.
It is an arithmetic number, because the mean of its divisors is an integer number (2166637104).
Almost surely, 214143325305 is an apocalyptic number.
It is an amenable number.
14143325305 is a deficient number, since it is larger than the sum of its proper divisors (3189771527).
14143325305 is an equidigital number, since it uses as much as digits as its factorization.
14143325305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60184415.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 14143325305 its reverse (50352334141), we get a palindrome (64495659446).
The spelling of 14143325305 in words is "fourteen billion, one hundred forty-three million, three hundred twenty-five thousand, three hundred five".
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