141433405511051 has 4 divisors (see below), whose sum is σ = 141433516760400. Its totient is φ = 141433294261704.

The previous prime is 141433405511033. The next prime is 141433405511053. The reversal of 141433405511051 is 150115504334141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141433405511051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141433405510996 and 141433405511014.

It is not an unprimeable number, because it can be changed into a prime (141433405511053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53695391 + ... + 56267768.

It is an arithmetic number, because the mean of its divisors is an integer number (35358379190100).

Almost surely, 2^{141433405511051} is an apocalyptic number.

141433405511051 is a deficient number, since it is larger than the sum of its proper divisors (111249349).

141433405511051 is a wasteful number, since it uses less digits than its factorization.

141433405511051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111249348.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 141433405511051 its reverse (150115504334141), we get a palindrome (291548909845192).

The spelling of 141433405511051 in words is "one hundred forty-one trillion, four hundred thirty-three billion, four hundred five million, five hundred eleven thousand, fifty-one".