Base | Representation |
---|---|
bin | 10100100101001101010… |
… | …011100101011100110000 |
3 | 12000012122212112021002111 |
4 | 110211031103211130300 |
5 | 141133032323021034 |
6 | 3001423412455104 |
7 | 204116460004336 |
oct | 24451523453460 |
9 | 5005585467074 |
10 | 1414341220144 |
11 | 4a5900824246 |
12 | 1aa13801a494 |
13 | a34aab16858 |
14 | 4c651145b56 |
15 | 26bcc1e5364 |
hex | 1494d4e5730 |
1414341220144 has 20 divisors (see below), whose sum is σ = 2859428989296. Its totient is φ = 676424061632.
The previous prime is 1414341220111. The next prime is 1414341220177. The reversal of 1414341220144 is 4410221434141.
It is an interprime number because it is at equal distance from previous prime (1414341220111) and next prime (1414341220177).
It is a super-2 number, since 2×14143412201442 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1921658899 + ... + 1921659634.
Almost surely, 21414341220144 is an apocalyptic number.
It is an amenable number.
1414341220144 is an abundant number, since it is smaller than the sum of its proper divisors (1445087769152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1414341220144 is a wasteful number, since it uses less digits than its factorization.
1414341220144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3843318564 (or 3843318558 counting only the distinct ones).
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 1414341220144 its reverse (4410221434141), we get a palindrome (5824562654285).
The spelling of 1414341220144 in words is "one trillion, four hundred fourteen billion, three hundred forty-one million, two hundred twenty thousand, one hundred forty-four".
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