14143420311151 has 4 divisors (see below), whose sum is σ = 14155196682304. Its totient is φ = 14131643940000.

The previous prime is 14143420311149. The next prime is 14143420311161. The reversal of 14143420311151 is 15111302434141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14143420311151 - 2¹ = 14143420311149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14143420311121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5888183775 + ... + 5888186176.

It is an arithmetic number, because the mean of its divisors is an integer number (3538799170576).

Almost surely, 2^{14143420311151} is an apocalyptic number.

14143420311151 is a deficient number, since it is larger than the sum of its proper divisors (11776371153).

14143420311151 is a wasteful number, since it uses less digits than its factorization.

14143420311151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11776371152.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 14143420311151 its reverse (15111302434141), we get a palindrome (29254722745292).

The spelling of 14143420311151 in words is "fourteen trillion, one hundred forty-three billion, four hundred twenty million, three hundred eleven thousand, one hundred fifty-one".