Base | Representation |
---|---|
bin | 1100110111010000101001… |
… | …0100100000110011001011 |
3 | 1212002002211212100101012110 |
4 | 3031310022110200303023 |
5 | 3323211342104030430 |
6 | 50025233455513403 |
7 | 2656556061163263 |
oct | 315641224406313 |
9 | 55062755311173 |
10 | 14143500455115 |
11 | 4563252317539 |
12 | 1705131828863 |
13 | 7b7959ab1755 |
14 | 36c7989367a3 |
15 | 197d890bb7b0 |
hex | cdd0a520ccb |
14143500455115 has 32 divisors (see below), whose sum is σ = 23382245855232. Its totient is φ = 7292790576000.
The previous prime is 14143500455083. The next prime is 14143500455167. The reversal of 14143500455115 is 51155400534141.
It is not a de Polignac number, because 14143500455115 - 25 = 14143500455083 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14271376 + ... + 15230205.
It is an arithmetic number, because the mean of its divisors is an integer number (730695182976).
Almost surely, 214143500455115 is an apocalyptic number.
14143500455115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14143500455115 is a deficient number, since it is larger than the sum of its proper divisors (9238745400117).
14143500455115 is a wasteful number, since it uses less digits than its factorization.
14143500455115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29502651.
The product of its (nonzero) digits is 120000, while the sum is 39.
Adding to 14143500455115 its reverse (51155400534141), we get a palindrome (65298900989256).
The spelling of 14143500455115 in words is "fourteen trillion, one hundred forty-three billion, five hundred million, four hundred fifty-five thousand, one hundred fifteen".
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