14143542131241 has 48 divisors (see below), whose sum is σ = 20768643441936. Its totient is φ = 9273965395968.

The previous prime is 14143542131239. The next prime is 14143542131249. The reversal of 14143542131241 is 14213124534141.

14143542131241 is a `hidden beast` number, since 1 + 4 + 1 + 43 + 542 + 1 + 31 + 2 + 41 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 2144218419225 + 11999323712016 = 1464315^2 + 3464004^2 .

It is not a de Polignac number, because 14143542131241 - 2¹ = 14143542131239 is a prime.

It is a super-3 number, since 3×14143542131241³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14143542131196 and 14143542131205.

It is not an unprimeable number, because it can be changed into a prime (14143542131249) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 123366841 + ... + 123481433.

It is an arithmetic number, because the mean of its divisors is an integer number (432680071707).

Almost surely, 2^{14143542131241} is an apocalyptic number.

It is an amenable number.

14143542131241 is a deficient number, since it is larger than the sum of its proper divisors (6625101310695).

14143542131241 is a wasteful number, since it uses less digits than its factorization.

14143542131241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115642 (or 115639 counting only the distinct ones).

The product of its digits is 46080, while the sum is 36.

Adding to 14143542131241 its reverse (14213124534141), we get a palindrome (28356666665382).

The spelling of 14143542131241 in words is "fourteen trillion, one hundred forty-three billion, five hundred forty-two million, one hundred thirty-one thousand, two hundred forty-one".