14144133040132 has 12 divisors (see below), whose sum is σ = 24756608365020. Its totient is φ = 7070816364416.

The previous prime is 14144133040127. The next prime is 14144133040133. The reversal of 14144133040132 is 23104033144141.

It can be written as a sum of positive squares in 2 ways, for example, as 5353050359556 + 8791082680576 = 2313666^2 + 2964976^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14144133040094 and 14144133040103.

It is not an unprimeable number, because it can be changed into a prime (14144133040133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312513457 + ... + 312558712.

It is an arithmetic number, because the mean of its divisors is an integer number (2063050697085).

Almost surely, 2^{14144133040132} is an apocalyptic number.

It is an amenable number.

14144133040132 is a deficient number, since it is larger than the sum of its proper divisors (10612475324888).

14144133040132 is a wasteful number, since it uses less digits than its factorization.

14144133040132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 625077830 (or 625077828 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14144133040132 its reverse (23104033144141), we get a palindrome (37248166184273).

The spelling of 14144133040132 in words is "fourteen trillion, one hundred forty-four billion, one hundred thirty-three million, forty thousand, one hundred thirty-two".