Base | Representation |
---|---|
bin | 1100110111010011000000… |
… | …0001101000100000001111 |
3 | 1212002011110221200000201120 |
4 | 3031310300001220200033 |
5 | 3323214141024241033 |
6 | 50025420334212023 |
7 | 2656610542105431 |
oct | 315646001504017 |
9 | 55064427600646 |
10 | 14144133040143 |
11 | 4563547400a87 |
12 | 1705289654013 |
13 | 7b7a2ab78b12 |
14 | 36c818962651 |
15 | 197dc48c41b3 |
hex | cdd3006880f |
14144133040143 has 8 divisors (see below), whose sum is σ = 19178485478400. Its totient is φ = 9269601314328.
The previous prime is 14144133040133. The next prime is 14144133040159. The reversal of 14144133040143 is 34104033144141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14144133040143 - 24 = 14144133040127 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14144133040133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39955177903 + ... + 39955178256.
It is an arithmetic number, because the mean of its divisors is an integer number (2397310684800).
Almost surely, 214144133040143 is an apocalyptic number.
14144133040143 is a deficient number, since it is larger than the sum of its proper divisors (5034352438257).
14144133040143 is an equidigital number, since it uses as much as digits as its factorization.
14144133040143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79910356221.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 14144133040143 its reverse (34104033144141), we get a palindrome (48248166184284).
The spelling of 14144133040143 in words is "fourteen trillion, one hundred forty-four billion, one hundred thirty-three million, forty thousand, one hundred forty-three".
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