Search a number
-
+
14144313002 = 27072156501
BaseRepresentation
bin11010010110001000…
…10001011010101010
31100111202000112210112
431023010101122222
5212431421004002
610255305414322
71010336451101
oct151304213252
940452015715
1014144313002
115aa9106786
1228a8a9a3a2
1314454993a1
14982721038
1557bb3c852
hex34b1116aa

14144313002 has 4 divisors (see below), whose sum is σ = 21216469506. Its totient is φ = 7072156500.

The previous prime is 14144312977. The next prime is 14144313019. The reversal of 14144313002 is 20031344141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20031344141 = 101631971007.

It can be written as a sum of positive squares in only one way, i.e., 13360816921 + 783496081 = 115589^2 + 27991^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3536078249 + ... + 3536078252.

Almost surely, 214144313002 is an apocalyptic number.

14144313002 is a deficient number, since it is larger than the sum of its proper divisors (7072156504).

14144313002 is an equidigital number, since it uses as much as digits as its factorization.

14144313002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7072156503.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14144313002 its reverse (20031344141), we get a palindrome (34175657143).

The spelling of 14144313002 in words is "fourteen billion, one hundred forty-four million, three hundred thirteen thousand, two".

Divisors: 1 2 7072156501 14144313002