14145052211335 has 4 divisors (see below), whose sum is σ = 16974062653608. Its totient is φ = 11316041769064.

The previous prime is 14145052211221. The next prime is 14145052211387. The reversal of 14145052211335 is 53311225054141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14145052211335 - 2²¹ = 14145050114183 is a prime.

It is a super-2 number, since 2×14145052211335² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14145052211294 and 14145052211303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1414505221129 + ... + 1414505221138.

It is an arithmetic number, because the mean of its divisors is an integer number (4243515663402).

Almost surely, 2^{14145052211335} is an apocalyptic number.

14145052211335 is a deficient number, since it is larger than the sum of its proper divisors (2829010442273).

14145052211335 is an equidigital number, since it uses as much as digits as its factorization.

14145052211335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2829010442272.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 14145052211335 its reverse (53311225054141), we get a palindrome (67456277265476).

The spelling of 14145052211335 in words is "fourteen trillion, one hundred forty-five billion, fifty-two million, two hundred eleven thousand, three hundred thirty-five".