Base | Representation |
---|---|
bin | 1000001111000110110… |
… | …0011111011110001011 |
3 | 111112012221210011122022 |
4 | 2003301230133132023 |
5 | 4304234421111041 |
6 | 145000145515055 |
7 | 13136231345012 |
oct | 2036154373613 |
9 | 445187704568 |
10 | 141493925771 |
11 | 550096a5740 |
12 | 2350a042a8b |
13 | 1045c238543 |
14 | 6bc3bcda79 |
15 | 3a31e6b24b |
hex | 20f1b1f78b |
141493925771 has 4 divisors (see below), whose sum is σ = 154357009944. Its totient is φ = 128630841600.
The previous prime is 141493925647. The next prime is 141493925777. The reversal of 141493925771 is 177529394141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141493925771 - 214 = 141493909387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141493925777) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6431542070 + ... + 6431542091.
It is an arithmetic number, because the mean of its divisors is an integer number (38589252486).
Almost surely, 2141493925771 is an apocalyptic number.
141493925771 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
141493925771 is a deficient number, since it is larger than the sum of its proper divisors (12863084173).
141493925771 is a wasteful number, since it uses less digits than its factorization.
141493925771 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12863084172.
The product of its digits is 1905120, while the sum is 53.
The spelling of 141493925771 in words is "one hundred forty-one billion, four hundred ninety-three million, nine hundred twenty-five thousand, seven hundred seventy-one".
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