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141500343313 = 720214334759
BaseRepresentation
bin1000001111001000010…
…0111110010000010001
3111112020101212012212001
42003302010332100101
54304243041441223
6145000535234001
713136340034030
oct2036204762021
9445211765761
10141500343313
115501228929a
1223510218901
13104606745c4
146bc49c0717
153a327d79ad
hex20f213e411

141500343313 has 4 divisors (see below), whose sum is σ = 161714678080. Its totient is φ = 121286008548.

The previous prime is 141500343263. The next prime is 141500343377. The reversal of 141500343313 is 313343005141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141500343313 - 221 = 141498246161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141500313313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10107167373 + ... + 10107167386.

It is an arithmetic number, because the mean of its divisors is an integer number (40428669520).

Almost surely, 2141500343313 is an apocalyptic number.

It is an amenable number.

141500343313 is a deficient number, since it is larger than the sum of its proper divisors (20214334767).

141500343313 is an equidigital number, since it uses as much as digits as its factorization.

141500343313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20214334766.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 141500343313 its reverse (313343005141), we get a palindrome (454843348454).

The spelling of 141500343313 in words is "one hundred forty-one billion, five hundred million, three hundred forty-three thousand, three hundred thirteen".

Divisors: 1 7 20214334759 141500343313