Base | Representation |
---|---|
bin | 11010010111001110… |
… | …00100010011110001 |
3 | 1100112101011221221100 |
4 | 31023213010103301 |
5 | 212441234344403 |
6 | 10300233115013 |
7 | 1010510131002 |
oct | 151347042361 |
9 | 40471157840 |
10 | 14153434353 |
11 | 6003276793 |
12 | 28abb58a69 |
13 | 1447341036 |
14 | 983a171a9 |
15 | 57c8402a3 |
hex | 34b9c44f1 |
14153434353 has 24 divisors (see below), whose sum is σ = 21415799808. Its totient is φ = 8990226432.
The previous prime is 14153434331. The next prime is 14153434357. The reversal of 14153434353 is 35343435141.
14153434353 is a `hidden beast` number, since 1 + 41 + 534 + 34 + 3 + 53 = 666.
14153434353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14153434353 - 226 = 14086325489 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14153434357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 79825 + ... + 186222.
It is an arithmetic number, because the mean of its divisors is an integer number (892324992).
Almost surely, 214153434353 is an apocalyptic number.
It is an amenable number.
14153434353 is a deficient number, since it is larger than the sum of its proper divisors (7262365455).
14153434353 is a wasteful number, since it uses less digits than its factorization.
14153434353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266333 (or 266330 counting only the distinct ones).
The product of its digits is 129600, while the sum is 36.
Adding to 14153434353 its reverse (35343435141), we get a palindrome (49496869494).
The spelling of 14153434353 in words is "fourteen billion, one hundred fifty-three million, four hundred thirty-four thousand, three hundred fifty-three".
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