Base | Representation |
---|---|
bin | 1000001111010100001… |
… | …1010100010100001011 |
3 | 111112100212202021122211 |
4 | 2003311003110110023 |
5 | 4304343330203120 |
6 | 145005520525551 |
7 | 13140514124320 |
oct | 2036503242413 |
9 | 445325667584 |
10 | 141550241035 |
11 | 5503846a185 |
12 | 23524a808b7 |
13 | 1046aac5298 |
14 | 6bcb48cb47 |
15 | 3a36d9225a |
hex | 20f50d450b |
141550241035 has 32 divisors (see below), whose sum is σ = 196595942400. Its totient is φ = 95833449600.
The previous prime is 141550240999. The next prime is 141550241047. The reversal of 141550241035 is 530142055141.
It is not a de Polignac number, because 141550241035 - 29 = 141550240523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141550240988 and 141550241006.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1213296 + ... + 1324834.
It is an arithmetic number, because the mean of its divisors is an integer number (6143623200).
Almost surely, 2141550241035 is an apocalyptic number.
141550241035 is a deficient number, since it is larger than the sum of its proper divisors (55045701365).
141550241035 is a wasteful number, since it uses less digits than its factorization.
141550241035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112011.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 141550241035 its reverse (530142055141), we get a palindrome (671692296176).
The spelling of 141550241035 in words is "one hundred forty-one billion, five hundred fifty million, two hundred forty-one thousand, thirty-five".
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