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141560623421 = 720222946203
BaseRepresentation
bin1000001111010110101…
…0111011000100111101
3111112101121021202121122
42003311222323010331
54304404004422141
6145010531240325
713141001305550
oct2036552730475
9445347252548
10141560623421
1155043310668
12235284490a5
131046ccbbbc9
146bcc9d2697
153a37c4364b
hex20f5abb13d

141560623421 has 4 divisors (see below), whose sum is σ = 161783569632. Its totient is φ = 121337677212.

The previous prime is 141560623409. The next prime is 141560623429. The reversal of 141560623421 is 124326065141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141560623421 - 214 = 141560607037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141560623429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10111473095 + ... + 10111473108.

It is an arithmetic number, because the mean of its divisors is an integer number (40445892408).

Almost surely, 2141560623421 is an apocalyptic number.

It is an amenable number.

141560623421 is a deficient number, since it is larger than the sum of its proper divisors (20222946211).

141560623421 is an equidigital number, since it uses as much as digits as its factorization.

141560623421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20222946210.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 141560623421 its reverse (124326065141), we get a palindrome (265886688562).

The spelling of 141560623421 in words is "one hundred forty-one billion, five hundred sixty million, six hundred twenty-three thousand, four hundred twenty-one".

Divisors: 1 7 20222946203 141560623421