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14156420433 = 34718806811
BaseRepresentation
bin11010010111100100…
…11101010101010001
31100112120210200001220
431023302131111101
5212443020423213
610300421115253
71010544405531
oct151362352521
940476720056
1014156420433
116004a26221
1228b0b58b29
131447b4824c
149841934c1
1557cc2ee23
hex34bc9d551

14156420433 has 4 divisors (see below), whose sum is σ = 18875227248. Its totient is φ = 9437613620.

The previous prime is 14156420407. The next prime is 14156420449. The reversal of 14156420433 is 33402465141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14156420433 - 213 = 14156412241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14156420394 and 14156420403.

It is not an unprimeable number, because it can be changed into a prime (14156420233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2359403403 + ... + 2359403408.

It is an arithmetic number, because the mean of its divisors is an integer number (4718806812).

Almost surely, 214156420433 is an apocalyptic number.

It is an amenable number.

14156420433 is a deficient number, since it is larger than the sum of its proper divisors (4718806815).

14156420433 is an equidigital number, since it uses as much as digits as its factorization.

14156420433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4718806814.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 14156420433 its reverse (33402465141), we get a palindrome (47558885574).

The spelling of 14156420433 in words is "fourteen billion, one hundred fifty-six million, four hundred twenty thousand, four hundred thirty-three".

Divisors: 1 3 4718806811 14156420433