Base | Representation |
---|---|
bin | 1000001111110001100… |
… | …0000101110011011111 |
3 | 111112200102222112200212 |
4 | 2003330120011303133 |
5 | 4310121310032020 |
6 | 145030030443035 |
7 | 13143535465661 |
oct | 2037430056337 |
9 | 445612875625 |
10 | 141673127135 |
11 | 550a0872341 |
12 | 2355a06347b |
13 | 1048a3bca57 |
14 | 6bdd91a531 |
15 | 3a42a67cc5 |
hex | 20fc605cdf |
141673127135 has 4 divisors (see below), whose sum is σ = 170007752568. Its totient is φ = 113338501704.
The previous prime is 141673127081. The next prime is 141673127161. The reversal of 141673127135 is 531721376141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141673127135 - 214 = 141673110751 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141673127092 and 141673127101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14167312709 + ... + 14167312718.
It is an arithmetic number, because the mean of its divisors is an integer number (42501938142).
Almost surely, 2141673127135 is an apocalyptic number.
141673127135 is a deficient number, since it is larger than the sum of its proper divisors (28334625433).
141673127135 is an equidigital number, since it uses as much as digits as its factorization.
141673127135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28334625432.
The product of its digits is 105840, while the sum is 41.
The spelling of 141673127135 in words is "one hundred forty-one billion, six hundred seventy-three million, one hundred twenty-seven thousand, one hundred thirty-five".
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