Base | Representation |
---|---|
bin | 11010011100110001… |
… | …10110101010110001 |
3 | 1100122121212210000121 |
4 | 31032120312222301 |
5 | 213040202240423 |
6 | 10305020050241 |
7 | 1011614230600 |
oct | 151630665261 |
9 | 40577783017 |
10 | 14200040113 |
11 | 6027609346 |
12 | 2903693981 |
13 | 1453bab4cc |
14 | 989ca9a37 |
15 | 58199945d |
hex | 34e636ab1 |
14200040113 has 12 divisors (see below), whose sum is σ = 16902565680. Its totient is φ = 11888403912.
The previous prime is 14200040087. The next prime is 14200040117. The reversal of 14200040113 is 31104000241.
It is not a de Polignac number, because 14200040113 - 213 = 14200031921 is a prime.
It is a super-2 number, since 2×142000401132 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14200040117) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3367623 + ... + 3371836.
It is an arithmetic number, because the mean of its divisors is an integer number (1408547140).
Almost surely, 214200040113 is an apocalyptic number.
It is an amenable number.
14200040113 is a deficient number, since it is larger than the sum of its proper divisors (2702525567).
14200040113 is an equidigital number, since it uses as much as digits as its factorization.
14200040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6739516 (or 6739509 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 14200040113 its reverse (31104000241), we get a palindrome (45304040354).
The spelling of 14200040113 in words is "fourteen billion, two hundred million, forty thousand, one hundred thirteen".
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