Base | Representation |
---|---|
bin | 10100101010100000101… |
… | …001111011100011111111 |
3 | 12000202100122112121001111 |
4 | 110222200221323203333 |
5 | 141231212321212421 |
6 | 3004204352422451 |
7 | 204410531360545 |
oct | 24524051734377 |
9 | 5022318477044 |
10 | 1420034554111 |
11 | 4a8262538328 |
12 | 1ab266847a27 |
13 | a3ba74bc614 |
14 | 4ca31327d95 |
15 | 26e11e53ee1 |
hex | 14aa0a7b8ff |
1420034554111 has 4 divisors (see below), whose sum is σ = 1433305905192. Its totient is φ = 1406763203032.
The previous prime is 1420034554109. The next prime is 1420034554129. The reversal of 1420034554111 is 1114554300241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1420034554111 - 21 = 1420034554109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420034554811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6635675380 + ... + 6635675593.
It is an arithmetic number, because the mean of its divisors is an integer number (358326476298).
Almost surely, 21420034554111 is an apocalyptic number.
1420034554111 is a deficient number, since it is larger than the sum of its proper divisors (13271351081).
1420034554111 is a wasteful number, since it uses less digits than its factorization.
1420034554111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13271351080.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1420034554111 its reverse (1114554300241), we get a palindrome (2534588854352).
The spelling of 1420034554111 in words is "one trillion, four hundred twenty billion, thirty-four million, five hundred fifty-four thousand, one hundred eleven".
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