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14200403353193 = 17029833895317
BaseRepresentation
bin1100111010100100100111…
…1111110101111001101001
31212021112201112012002211002
43032221021333311321221
53330124411224300233
650111324130244345
72663642142633311
oct316511177657151
955245645162732
1014200403353193
1145853a2542032
1217141724266b5
137c01279b9a45
14371435d48441
151995b99996e8
hexcea49ff5e69

14200403353193 has 4 divisors (see below), whose sum is σ = 14201237265540. Its totient is φ = 14199569440848.

The previous prime is 14200403353139. The next prime is 14200403353231. The reversal of 14200403353193 is 39135330400241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8962676775529 + 5237726577664 = 2993773^2 + 2288608^2 .

It is a cyclic number.

It is not a de Polignac number, because 14200403353193 - 222 = 14200399158889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14200403353133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416930630 + ... + 416964687.

It is an arithmetic number, because the mean of its divisors is an integer number (3550309316385).

Almost surely, 214200403353193 is an apocalyptic number.

It is an amenable number.

14200403353193 is a deficient number, since it is larger than the sum of its proper divisors (833912347).

14200403353193 is an equidigital number, since it uses as much as digits as its factorization.

14200403353193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 833912346.

The product of its (nonzero) digits is 116640, while the sum is 38.

The spelling of 14200403353193 in words is "fourteen trillion, two hundred billion, four hundred three million, three hundred fifty-three thousand, one hundred ninety-three".

Divisors: 1 17029 833895317 14200403353193