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1420120123 = 8317109881
BaseRepresentation
bin101010010100101…
…0101000000111011
310122222012120120121
41110221111000323
510402022320443
6352530034111
750122551622
oct12451250073
93588176517
101420120123
116696912a4
12337718937
131982a4786
14d686c6b9
1584a1b4ed
hex54a5503b

1420120123 has 4 divisors (see below), whose sum is σ = 1437230088. Its totient is φ = 1403010160.

The previous prime is 1420120081. The next prime is 1420120127. The reversal of 1420120123 is 3210210241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1420120123 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1420120097 and 1420120106.

It is not an unprimeable number, because it can be changed into a prime (1420120127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8554858 + ... + 8555023.

It is an arithmetic number, because the mean of its divisors is an integer number (359307522).

Almost surely, 21420120123 is an apocalyptic number.

1420120123 is a deficient number, since it is larger than the sum of its proper divisors (17109965).

1420120123 is an equidigital number, since it uses as much as digits as its factorization.

1420120123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17109964.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1420120123 is about 37684.4811958451. The cubic root of 1420120123 is about 1124.0225578883.

Adding to 1420120123 its reverse (3210210241), we get a palindrome (4630330364).

The spelling of 1420120123 in words is "one billion, four hundred twenty million, one hundred twenty thousand, one hundred twenty-three".

Divisors: 1 83 17109881 1420120123