Base | Representation |
---|---|
bin | 10100101010100101111… |
… | …011011000110100110111 |
3 | 12000202120210222221122101 |
4 | 110222211323120310313 |
5 | 141231402443012003 |
6 | 3004221232442531 |
7 | 204412654320442 |
oct | 24524573306467 |
9 | 5022523887571 |
10 | 1420123016503 |
11 | 4a82a8469444 |
12 | 1ab2903a9447 |
13 | a3bbc923729 |
14 | 4ca3cd94659 |
15 | 26e19aca11d |
hex | 14aa5ed8d37 |
1420123016503 has 4 divisors (see below), whose sum is σ = 1420126593480. Its totient is φ = 1420119439528.
The previous prime is 1420123016491. The next prime is 1420123016549. The reversal of 1420123016503 is 3056103210241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1420123016503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420123016303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1106200 + ... + 2015917.
It is an arithmetic number, because the mean of its divisors is an integer number (355031648370).
Almost surely, 21420123016503 is an apocalyptic number.
1420123016503 is a deficient number, since it is larger than the sum of its proper divisors (3576977).
1420123016503 is an equidigital number, since it uses as much as digits as its factorization.
1420123016503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3576976.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1420123016503 its reverse (3056103210241), we get a palindrome (4476226226744).
The spelling of 1420123016503 in words is "one trillion, four hundred twenty billion, one hundred twenty-three million, sixteen thousand, five hundred three".
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