14202211343441 has 32 divisors (see below), whose sum is σ = 16690995509760. Its totient is φ = 11939752864000.

The previous prime is 14202211343371. The next prime is 14202211343483. The reversal of 14202211343441 is 14434311220241.

14202211343441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14202211343441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14202211343398 and 14202211343407.

It is not an unprimeable number, because it can be changed into a prime (14202211343741) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22046366 + ... + 22681416.

It is an arithmetic number, because the mean of its divisors is an integer number (521593609680).

Almost surely, 2^{14202211343441} is an apocalyptic number.

14202211343441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14202211343441 is a deficient number, since it is larger than the sum of its proper divisors (2488784166319).

14202211343441 is a wasteful number, since it uses less digits than its factorization.

14202211343441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637165.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 14202211343441 its reverse (14434311220241), we get a palindrome (28636522563682).

The spelling of 14202211343441 in words is "fourteen trillion, two hundred two billion, two hundred eleven million, three hundred forty-three thousand, four hundred forty-one".