Base | Representation |
---|---|
bin | 1000010001000101000… |
… | …0000011100101100001 |
3 | 111120120211222022202211 |
4 | 2010101100003211201 |
5 | 4311330433424213 |
6 | 145124501042121 |
7 | 13155320330560 |
oct | 2042120034541 |
9 | 446524868684 |
10 | 142023342433 |
11 | 55260524275 |
12 | 236373b6341 |
13 | 10514b1cc3b |
14 | 6c34241bd7 |
15 | 3a6369553d |
hex | 2111403961 |
142023342433 has 16 divisors (see below), whose sum is σ = 167656559616. Its totient is φ = 117731243520.
The previous prime is 142023342431. The next prime is 142023342443. The reversal of 142023342433 is 334243320241.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 142023342433 - 21 = 142023342431 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 142023342395 and 142023342404.
It is not an unprimeable number, because it can be changed into a prime (142023342431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 126285 + ... + 547717.
It is an arithmetic number, because the mean of its divisors is an integer number (10478534976).
Almost surely, 2142023342433 is an apocalyptic number.
It is an amenable number.
142023342433 is a deficient number, since it is larger than the sum of its proper divisors (25633217183).
142023342433 is a wasteful number, since it uses less digits than its factorization.
142023342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 423024.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 142023342433 its reverse (334243320241), we get a palindrome (476266662674).
The spelling of 142023342433 in words is "one hundred forty-two billion, twenty-three million, three hundred forty-two thousand, four hundred thirty-three".
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