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1420301325155 = 513911969170741
BaseRepresentation
bin10100101010110000100…
…011100101001101100011
312000210001020111222010112
4110222300203211031203
5141232234114401110
63004251042321535
7204420251032646
oct24526043451543
95023036458115
101420301325155
114a838a086369
121ab3200592ab
13a3c1a8547cb
144ca5892ba5d
1526e2a59c405
hex14ab08e5363

1420301325155 has 16 divisors (see below), whose sum is σ = 1716776661600. Its totient is φ = 1127965808640.

The previous prime is 1420301325143. The next prime is 1420301325239. The reversal of 1420301325155 is 5515231030241.

It is not a de Polignac number, because 1420301325155 - 218 = 1420301063011 is a prime.

It is a super-3 number, since 3×14203013251553 (a number of 37 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8233085 + ... + 8403825.

It is an arithmetic number, because the mean of its divisors is an integer number (107298541350).

Almost surely, 21420301325155 is an apocalyptic number.

1420301325155 is a deficient number, since it is larger than the sum of its proper divisors (296475336445).

1420301325155 is a wasteful number, since it uses less digits than its factorization.

1420301325155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182854.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 1420301325155 its reverse (5515231030241), we get a palindrome (6935532355396).

The spelling of 1420301325155 in words is "one trillion, four hundred twenty billion, three hundred one million, three hundred twenty-five thousand, one hundred fifty-five".

Divisors: 1 5 139 695 11969 59845 170741 853705 1663691 8318455 23732999 118664995 2043599029 10217995145 284060265031 1420301325155