Base | Representation |
---|---|
bin | 1100111010101110011000… |
… | …1001100000011000110011 |
3 | 1212021210111002202200000121 |
4 | 3032223212021200120303 |
5 | 3330200242410212321 |
6 | 50112440113231111 |
7 | 2664064103453104 |
oct | 316534611403063 |
9 | 55253432680017 |
10 | 14203023132211 |
11 | 4586517316861 |
12 | 1714783862497 |
13 | 7c0454696644 |
14 | 371603c583ab |
15 | 1996be985441 |
hex | ceae6260633 |
14203023132211 has 4 divisors (see below), whose sum is σ = 14203226128624. Its totient is φ = 14202820135800.
The previous prime is 14203023132203. The next prime is 14203023132253. The reversal of 14203023132211 is 11223132030241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14203023132211 - 23 = 14203023132203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14203023132911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101393220 + ... + 101533201.
It is an arithmetic number, because the mean of its divisors is an integer number (3550806532156).
Almost surely, 214203023132211 is an apocalyptic number.
14203023132211 is a deficient number, since it is larger than the sum of its proper divisors (202996413).
14203023132211 is an equidigital number, since it uses as much as digits as its factorization.
14203023132211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 202996412.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14203023132211 its reverse (11223132030241), we get a palindrome (25426155162452).
The spelling of 14203023132211 in words is "fourteen trillion, two hundred three billion, twenty-three million, one hundred thirty-two thousand, two hundred eleven".
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