14203113411341 has 4 divisors (see below), whose sum is σ = 14240197258752. Its totient is φ = 14166029563932.

The previous prime is 14203113411317. The next prime is 14203113411359. The reversal of 14203113411341 is 14311431130241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14203113411341 is a prime.

It is a super-3 number, since 3×14203113411341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14203113411391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18541923131 + ... + 18541923896.

It is an arithmetic number, because the mean of its divisors is an integer number (3560049314688).

Almost surely, 2^{14203113411341} is an apocalyptic number.

It is an amenable number.

14203113411341 is a deficient number, since it is larger than the sum of its proper divisors (37083847411).

14203113411341 is an equidigital number, since it uses as much as digits as its factorization.

14203113411341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37083847410.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 14203113411341 its reverse (14311431130241), we get a palindrome (28514544541582).

The spelling of 14203113411341 in words is "fourteen trillion, two hundred three billion, one hundred thirteen million, four hundred eleven thousand, three hundred forty-one".