142034100122101 has 4 divisors (see below), whose sum is σ = 154946291042304. Its totient is φ = 129121909201900.

The previous prime is 142034100122077. The next prime is 142034100122141. The reversal of 142034100122101 is 101221001430241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142034100122101 - 2⁵ = 142034100122069 is a prime.

It is a super-2 number, since 2×142034100122101² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142034100122141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6456095460085 + ... + 6456095460106.

It is an arithmetic number, because the mean of its divisors is an integer number (38736572760576).

Almost surely, 2^{142034100122101} is an apocalyptic number.

142034100122101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

142034100122101 is a deficient number, since it is larger than the sum of its proper divisors (12912190920203).

142034100122101 is a wasteful number, since it uses less digits than its factorization.

142034100122101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12912190920202.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 142034100122101 its reverse (101221001430241), we get a palindrome (243255101552342).

The spelling of 142034100122101 in words is "one hundred forty-two trillion, thirty-four billion, one hundred million, one hundred twenty-two thousand, one hundred one".