142043312131 has 4 divisors (see below), whose sum is σ = 162335213872. Its totient is φ = 121751410392.

The previous prime is 142043312053. The next prime is 142043312141. The reversal of 142043312131 is 131213340241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142043312131 - 2⁷ = 142043312003 is a prime.

It is a super-2 number, since 2×142043312131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142043312096 and 142043312105.

It is not an unprimeable number, because it can be changed into a prime (142043312141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10145950860 + ... + 10145950873.

It is an arithmetic number, because the mean of its divisors is an integer number (40583803468).

Almost surely, 2^142043312131 is an apocalyptic number.

142043312131 is a deficient number, since it is larger than the sum of its proper divisors (20291901741).

142043312131 is an equidigital number, since it uses as much as digits as its factorization.

142043312131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20291901740.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 142043312131 its reverse (131213340241), we get a palindrome (273256652372).

The spelling of 142043312131 in words is "one hundred forty-two billion, forty-three million, three hundred twelve thousand, one hundred thirty-one".