14204420210231 has 4 divisors (see below), whose sum is σ = 14229921862872. Its totient is φ = 14178918557592.

The previous prime is 14204420210207. The next prime is 14204420210237. The reversal of 14204420210231 is 13201202440241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14204420210231 is a prime.

It is a super-3 number, since 3×14204420210231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14204420210231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14204420210237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12750825485 + ... + 12750826598.

It is an arithmetic number, because the mean of its divisors is an integer number (3557480465718).

Almost surely, 2^{14204420210231} is an apocalyptic number.

14204420210231 is a deficient number, since it is larger than the sum of its proper divisors (25501652641).

14204420210231 is an equidigital number, since it uses as much as digits as its factorization.

14204420210231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25501652640.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 14204420210231 its reverse (13201202440241), we get a palindrome (27405622650472).

The spelling of 14204420210231 in words is "fourteen trillion, two hundred four billion, four hundred twenty million, two hundred ten thousand, two hundred thirty-one".